Integrand size = 11, antiderivative size = 71 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=-5 a b \sqrt {a+\frac {b}{x}}-\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}+\left (a+\frac {b}{x}\right )^{5/2} x+5 a^{3/2} b \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 71, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.455, Rules used = {248, 43, 52, 65, 214} \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=5 a^{3/2} b \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right )+x \left (a+\frac {b}{x}\right )^{5/2}-\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}-5 a b \sqrt {a+\frac {b}{x}} \]
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Rule 43
Rule 52
Rule 65
Rule 214
Rule 248
Rubi steps \begin{align*} \text {integral}& = -\text {Subst}\left (\int \frac {(a+b x)^{5/2}}{x^2} \, dx,x,\frac {1}{x}\right ) \\ & = \left (a+\frac {b}{x}\right )^{5/2} x-\frac {1}{2} (5 b) \text {Subst}\left (\int \frac {(a+b x)^{3/2}}{x} \, dx,x,\frac {1}{x}\right ) \\ & = -\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}+\left (a+\frac {b}{x}\right )^{5/2} x-\frac {1}{2} (5 a b) \text {Subst}\left (\int \frac {\sqrt {a+b x}}{x} \, dx,x,\frac {1}{x}\right ) \\ & = -5 a b \sqrt {a+\frac {b}{x}}-\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}+\left (a+\frac {b}{x}\right )^{5/2} x-\frac {1}{2} \left (5 a^2 b\right ) \text {Subst}\left (\int \frac {1}{x \sqrt {a+b x}} \, dx,x,\frac {1}{x}\right ) \\ & = -5 a b \sqrt {a+\frac {b}{x}}-\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}+\left (a+\frac {b}{x}\right )^{5/2} x-\left (5 a^2\right ) \text {Subst}\left (\int \frac {1}{-\frac {a}{b}+\frac {x^2}{b}} \, dx,x,\sqrt {a+\frac {b}{x}}\right ) \\ & = -5 a b \sqrt {a+\frac {b}{x}}-\frac {5}{3} b \left (a+\frac {b}{x}\right )^{3/2}+\left (a+\frac {b}{x}\right )^{5/2} x+5 a^{3/2} b \tanh ^{-1}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right ) \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 64, normalized size of antiderivative = 0.90 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=\frac {\sqrt {a+\frac {b}{x}} \left (-2 b^2-14 a b x+3 a^2 x^2\right )}{3 x}+5 a^{3/2} b \text {arctanh}\left (\frac {\sqrt {a+\frac {b}{x}}}{\sqrt {a}}\right ) \]
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Time = 0.04 (sec) , antiderivative size = 94, normalized size of antiderivative = 1.32
method | result | size |
risch | \(\frac {\left (3 a^{2} x^{2}-14 a b x -2 b^{2}\right ) \sqrt {\frac {a x +b}{x}}}{3 x}+\frac {5 a^{\frac {3}{2}} b \ln \left (\frac {\frac {b}{2}+a x}{\sqrt {a}}+\sqrt {a \,x^{2}+b x}\right ) \sqrt {\frac {a x +b}{x}}\, \sqrt {x \left (a x +b \right )}}{2 \left (a x +b \right )}\) | \(94\) |
default | \(-\frac {\sqrt {\frac {a x +b}{x}}\, \left (-30 \sqrt {a \,x^{2}+b x}\, a^{\frac {5}{2}} x^{3}-15 \ln \left (\frac {2 \sqrt {a \,x^{2}+b x}\, \sqrt {a}+2 a x +b}{2 \sqrt {a}}\right ) a^{2} b \,x^{3}+24 \left (a \,x^{2}+b x \right )^{\frac {3}{2}} a^{\frac {3}{2}} x +4 \left (a \,x^{2}+b x \right )^{\frac {3}{2}} b \sqrt {a}\right )}{6 x^{2} \sqrt {x \left (a x +b \right )}\, \sqrt {a}}\) | \(120\) |
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Time = 0.28 (sec) , antiderivative size = 139, normalized size of antiderivative = 1.96 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=\left [\frac {15 \, a^{\frac {3}{2}} b x \log \left (2 \, a x + 2 \, \sqrt {a} x \sqrt {\frac {a x + b}{x}} + b\right ) + 2 \, {\left (3 \, a^{2} x^{2} - 14 \, a b x - 2 \, b^{2}\right )} \sqrt {\frac {a x + b}{x}}}{6 \, x}, -\frac {15 \, \sqrt {-a} a b x \arctan \left (\frac {\sqrt {-a} \sqrt {\frac {a x + b}{x}}}{a}\right ) - {\left (3 \, a^{2} x^{2} - 14 \, a b x - 2 \, b^{2}\right )} \sqrt {\frac {a x + b}{x}}}{3 \, x}\right ] \]
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Time = 2.13 (sec) , antiderivative size = 99, normalized size of antiderivative = 1.39 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=a^{\frac {5}{2}} x \sqrt {1 + \frac {b}{a x}} - \frac {14 a^{\frac {3}{2}} b \sqrt {1 + \frac {b}{a x}}}{3} - \frac {5 a^{\frac {3}{2}} b \log {\left (\frac {b}{a x} \right )}}{2} + 5 a^{\frac {3}{2}} b \log {\left (\sqrt {1 + \frac {b}{a x}} + 1 \right )} - \frac {2 \sqrt {a} b^{2} \sqrt {1 + \frac {b}{a x}}}{3 x} \]
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Time = 0.30 (sec) , antiderivative size = 78, normalized size of antiderivative = 1.10 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=\sqrt {a + \frac {b}{x}} a^{2} x - \frac {5}{2} \, a^{\frac {3}{2}} b \log \left (\frac {\sqrt {a + \frac {b}{x}} - \sqrt {a}}{\sqrt {a + \frac {b}{x}} + \sqrt {a}}\right ) - \frac {2}{3} \, {\left (a + \frac {b}{x}\right )}^{\frac {3}{2}} b - 4 \, \sqrt {a + \frac {b}{x}} a b \]
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Exception generated. \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=\text {Exception raised: TypeError} \]
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Time = 6.03 (sec) , antiderivative size = 34, normalized size of antiderivative = 0.48 \[ \int \left (a+\frac {b}{x}\right )^{5/2} \, dx=-\frac {2\,x\,{\left (a+\frac {b}{x}\right )}^{5/2}\,{{}}_2{\mathrm {F}}_1\left (-\frac {5}{2},-\frac {3}{2};\ -\frac {1}{2};\ -\frac {a\,x}{b}\right )}{3\,{\left (\frac {a\,x}{b}+1\right )}^{5/2}} \]
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